#Palindrome permutation how to#
Therefore, this function is quite efficient. Hello Guys, In this tutorial we gone see how to get the permutations of all the words and to check if any permutation of the word is palindrome and print. The time complexity of this function is O(n), where n is the length of the string, because we iterate over the string once. I don't know why we are checking for the condition (bitVector & mask) 0. We then count the occurrences of each character using a Map, and we also keep track of the number of characters that have an odd count.įinally, we return true if there is at most one character with an odd count, which is the condition for a string to be a palindrome permutation. Palindrome Permutation (Cracking the Coding Interview 1.4) Ask Question Asked 6 years, 8 months ago Modified 3 years, 10 months ago Viewed 2k times 7 I'm having trouble understanding the bit logic in these two functions. In this isPalindromePermutation function, we first normalize the string by converting to lowercase and ignoring spaces. Given a phrase, you are to determine if any permutation of the phrase (ignoring whitespace and punctuation) is a palindrome, which is a. Here is a JavaScript function that checks if a given string is a palindrome permutation: function isPalindromePermutation(str) console.log(isPalindromePermutation('Tact Coa')) // Should print: true console.log(isPalindromePermutation('Not a Palindrome')) // Should print: false Explanation To make a string palindrome, we need an even number of occurrences of letters so that the string reads the same from left and right.
#Palindrome permutation software#
In a palindrome, characters have to appear in pairs for the string to be mirrored around the center, except possibly for one character, which can be unpaired and sit in the middle in case of an odd length string. Walmart Interview Questions for Software Developer: Palindrome Permutation You are given a string S, check if there exists any permutation of the given. Here is the javascript solutionĪ string is a palindrome permutation if it can be rearranged to form a palindrome.
In a palindrome, characters have to appear in pairs for the string to be mirrored around the center, except possibly for one character. In general, we don't need to consider the permutations of letters on the right because the string is fixed once the string on the left is chosen, so the number of palindromes is just the number of choices for the string of letters on the left, which is 30.
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